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p^2+((7/4)p)-(2/4)=0
Domain of the equation: 4)p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
p^2+((+7/4)p)-(+2/4)=0
We get rid of parentheses
p^2+((+7/4)p)-2/4=0
We calculate fractions
p^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$p=\frac{-b}{2a}=\frac{0}{2}=0$
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